minor corr

Doc/UserManual/BornAgainManual.tex

@@ -28,7 +28,7 @@
 
 %\documentclass[a4paper,11pt,twoside,fleqn]{report}
 \documentclass[a4paper,11pt,fleqn,draft]{report}
-%\usepackage[final]{graphicx}
+\usepackage[final]{graphicx}
 
 \input{Setup}
 

Doc/UserManual/Multilayers.tex

@@ -180,8 +180,9 @@ associated with the plane-wave solution (\ref{Eplawafa},\ref{Ephizwj}):
 \end{equation}
 The first two terms describe the exponential intensity decrease
 due to absorption.
-the oscillatory term in square brackets
-is a wave-mechanical subtlety that must not interest us.
+The oscillatory term in square brackets
+is a wave-mechanical subtlety
+of no interest for us.
 In the special case of a pure imaginary~$k_{\perp \il}$,
 the flux direction is $\k'=\k_\plll$.
 Then $\psi_\il(\r)$ is an \E{evanescent wave},
@@ -386,13 +387,16 @@ it may be an interesting exercise to make
 Consider a system
 with a single interface between two semi-infinite,
 non-absorbing media.
-After normalization to the incident vertical flux $J_{0\perp}^-=-Kf_0$,
-the reflected flux is
+The reflected flux,
+normalized to the incident vertical flux $J_{0\perp}^-=-Kf_0$,
+is
+\index{Reflected flux}%
 \begin{equation}
   \frac{J_{0\perp}^+}{J_{0\perp}^-}
   = - \left(\frac{f_0-f_1}{f_0+f_1}\right)^2,
 \end{equation}
 and the transmitted flux
+\index{Trasmitted flux}%
 \begin{equation}
   \frac{J_{1\perp}^-}{J_{0\perp}^-}
   = \frac{4f_0 f_1}{(f_0+f_1)^2}.